贪心之To Fill or Not to Fill

贪心之To Fill or Not to Fill

时间： 1ms        内存：64M

描述：

With highways available, driving a car from Hangzhou to any other city is easy. But since the tank capacity of a car is limited, we have to find gas stations on the way from time to time. Different gas station may give different price. You are asked to carefully design the cheapest route to go.

输入：

For each case, the first line contains 4 positive numbers: Cmax (<= 100), the maximum capacity of the tank; D (<=30000), the distance between Hangzhou and the destination city; Davg (<=20), the average distance per unit gas that the car can run; and N (<= 500), the total number of gas stations. Then N lines follow, each contains a pair of non-negative numbers: Pi, the unit gas price, and Di (<=D), the distance between this station and Hangzhou, for i=1,...N. All the numbers in a line are separated by a space.

输出：

For each test case, print the cheapest price in a line, accurate up to 2 decimal places. It is assumed that the tank is empty at the beginning. If it is impossible to reach the destination, print "The maximum travel distance = X" where X is the maximum possible distance the car can run, accurate up to 2 decimal places.

示例输入：

50 1300 12 8
6.00 1250
7.00 600
7.00 150
7.10 0
7.20 200
7.50 400
7.30 1000
6.85 300
50 1300 12 2
7.10 0
7.00 600

示例输出：

749.17
The maximum travel distance = 1200.00

提示：

参考答案：

解锁文章

没有看到答案？微信扫描二维码可免费解锁文章

使用微信扫描二维码打开广告页面后可以立即关闭，再刷新此页面即可正常浏览此文章

所跳转广告均由第三方提供，并不代表本站观点！

已经扫描此二维码？点此立即跳转

文章解锁成功，即将自动跳转，点此立即跳转