我想放假
时间: 1ms 内存:128M
描述:
小明的弟弟上小学了,每次刚入学就想知道什么时候放假,但是每学期开学的日子和每学期的有效天数都不一样,请你编程帮他计算放假日期。本题只需要提交填空部分
#include <iostream>
using namespace std;
class Date
{
public:
void input(int y,int m,int d);
friend Date operator+(Date &c,int &day);
void display();
private:
int year;
int month;
int day;
};void Date::input(int y,int m,int d)
{
year=y;
month=m;
day=d;
}
Date operator+(Date &c,int &day)
{
/*********************/填空部分
/*********************/
}void Date::display()
{
cout<<year<<"/"<<month<<"/"<<day<<endl;
}
int main()
{
Date date1,date2;
int y,m,d;
int day;
cin>>y>>m>>d;
date1.input(y,m,d);
cin>>day;
date2=date1+day;
date2.display();
return 0;
}
输入:
第一行输入开学的年月日,以空格隔开;第二行输入本学期的有效天数
输出:
输出计算后得到的放假日期,格式为年/月/日。
示例输入:
2008 2 29
140
示例输出:
2008/7/18
提示:
参考答案(内存最优[1484]):
#include <iostream>
using namespace std;
class Date
{
public:
void input(int y,int m,int d);
friend Date operator+(Date &c,int &day);
void display();
private:
int year;
int month;
int day;
};
void Date::input(int y,int m,int d)
{
year=y;
month=m;
day=d;
}
Date operator+(Date &c,int &day)
{
Date date;
date=c;
date.day+=day;
while(1)
{
switch(date.month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
if(date.day>31)
{
++date.month;
date.day-=31;
}
break;
case 4:
case 6:
case 9:
case 11:
if(date.day>30)
{
++date.month;
date.day-=30;
}
break;
case 2:
if((date.year%4==0&&date.year%100!=0)||date.year%400==0)
{
if(date.day>29)
{
++date.month;
date.day-=29;
}
}
else
{
if(date.day>28)
{
++date.month;
date.day-=28;
}
}
break;
}
if(date.month>12)
{
++date.year;
date.month-=12;
}
//cout<<"m:"<<date.month<<"d:"<<date.day<<endl;
if(((date.year%4==0&&date.year%100!=0)||date.year%400==0)&&date.month==2&&date.day<=29)
break;
else if(date.month==2&&date.day<=28)
break;
else if((date.month==1||date.month==3||date.month==5||date.month==7||date.month==8||date.month==10||date.month==12)&&date.day<=31)
break;
else if(date.day<=30)
break;
}
return date;
}
void Date::display()
{
cout<<year<<"/"<<month<<"/"<<day<<endl;
}
int main()
{
Date date1,date2;
int y,m,d;
int day;
cin>>y>>m>>d;
date1.input(y,m,d);
cin>>day;
date2=date1+day;
date2.display();
return 0;
}
参考答案(时间最优[0]):
#include <iostream>
using namespace std;
class Date
{
public:
void input(int y,int m,int d);
friend Date operator+(Date &c,int &day);
void display();
private:
int year;
int month;
int day;
};
void Date::input(int y,int m,int d)
{
year=y;
month=m;
day=d;
}
Date operator+(Date &c,int &day)
{
Date date;
date=c;
date.day+=day;
while(1)
{
switch(date.month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
if(date.day>31)
{
++date.month;
date.day-=31;
}
break;
case 4:
case 6:
case 9:
case 11:
if(date.day>30)
{
++date.month;
date.day-=30;
}
break;
case 2:
if((date.year%4==0&&date.year%100!=0)||date.year%400==0)
{
if(date.day>29)
{
++date.month;
date.day-=29;
}
}
else
{
if(date.day>28)
{
++date.month;
date.day-=28;
}
}
break;
}
if(date.month>12)
{
++date.year;
date.month-=12;
}
//cout<<"m:"<<date.month<<"d:"<<date.day<<endl;
if(((date.year%4==0&&date.year%100!=0)||date.year%400==0)&&date.month==2&&date.day<=29)
break;
else if(date.month==2&&date.day<=28)
break;
else if((date.month==1||date.month==3||date.month==5||date.month==7||date.month==8||date.month==10||date.month==12)&&date.day<=31)
break;
else if(date.day<=30)
break;
}
return date;
}
void Date::display()
{
cout<<year<<"/"<<month<<"/"<<day<<endl;
}
int main()
{
Date date1,date2;
int y,m,d;
int day;
cin>>y>>m>>d;
date1.input(y,m,d);
cin>>day;
date2=date1+day;
date2.display();
return 0;
}
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