Quicksum

Quicksum

时间: 1ms        内存:64M

描述:

A checksum is an algorithm that scans a packet of data and returns a single number. The idea is that if the packet is changed, the checksum will also change, so checksums are often used for detecting transmission errors, validating document contents, and in many other situations where it is necessary to detect undesirable changes in data.

For this problem, you will implement a checksum algorithm called Quicksum. A Quicksum packet allows only uppercase letters and spaces. It always begins and ends with an uppercase letter. Otherwise, spaces and letters can occur in any combination, including consecutive spaces.

A Quicksum is the sum of the products of each character's position in the packet times the character's value. A space has a value of zero, while letters have a value equal to their position in the alphabet. So, A=1, B=2, etc., through Z=26. Here are example Quicksum calculations for the packets "ACM" and "MID CENTRAL":

ACM: 1*1 + 2*3 + 3*13 = 46

MID CENTRAL: 1*13 + 2*9 + 3*4 + 4*0 + 5*3 + 6*5 + 7*14 + 8*20 + 9*18 + 10*1 + 11*12 = 650

输入:

The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 255 characters.

输出:

For each packet, output its Quicksum on a separate line in the output.

示例输入:

ACM
MID CENTRAL
REGIONAL PROGRAMMING CONTEST
ACN
A C M
ABC
BBC
#

示例输出:

46
650
4690
49
75
14
15

提示:

参考答案(内存最优[748]):

#include<stdio.h>
 int main()
 {
     char c;
     while((c=getchar())!='#')
     {
         int i=1,sum=0;
         do
         {
             sum+=i*(c==' '?0:c-'A'+1);
             i++;
         }
             while((c=getchar())!=10);
             printf("%d\n",sum);
     }
     return 0;
}

参考答案(时间最优[0]):

#include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
int main()
{
    char word[100000];
    int sum,length,i;
    while(cin.getline(word,sizeof(word)))
    {
        if(string(word)=="#")
            break;
        sum=0;
        length=strlen(word);
        for(i=0; i<length; i++)
        {
            while(word[i]==' ')
                i++;
            sum+=(i+1)*(int)(word[i]-64);
        }
        cout<<sum<<endl;
    }
    return 0;
}

题目和答案均来自于互联网,仅供参考,如有问题请联系管理员修改或删除。

点赞

发表评论

电子邮件地址不会被公开。必填项已用 * 标注